
CORRECTION FACTOR TO BE USED FOR DETERMINING
THE ACTUAL POWER/ENERGY AFTER
CONSIDERATION OF
RATIO AND PHASE ANGLE ERRORS OF
C.TS. AND P.TS.
USED IN
METERING.
It would be seen from the vector diagram that the meter reading shall be corresponding to Vs.Is.Cos a which does not correspond to the power/energy which shall be VICos f. A correction needs to be applied to the meter reading depending upon the errors of C.Ts. and P.Ts.
Phase angle seen by the meter is a which obviously is
a = f - q ± d
In the vector diagram d is shown as positive that is P.T. secondary voltage leads the primary voltage reversed. The phase angle of meter pressure coil is ignored and is assumed to be zero.
V - System Voltage
I - System Current
f - Load P.F
Is
Vs - P.T Secondary Voltage
q - Phase angle error C.T
d - Phase
angle error P.T
a
- Phase angle seen by meter
Thus, the correction corresponding to phase angle errors of C.Ts
and P.Ts. shall be
K = Cos f
Cos
(f - q ±
Note - d may be positive or negative.
About ratio errors of C.Ts and P.Ts. let the C.T. ratio error be e%
and P.T. ratio error be p%.
Actual Ratio of C.T. = RCTA = Primary Current
Actual Secondary Current
Actual Ratio of P.T. = RPTA = Primary Voltage
Actual Secondary Voltage
Considering the rated primary current (Ip) as primary current
(100%) for C.T. and rated primary voltage Vp (100%) as primary
voltage for P.T, (Errors e and p are assumed to be at rated primary
current and rated primary voltage with rated burden connected
across the secondary.
Actual Ratio of C.T. = Ip
Is - e x Is 100 (2) Actual Ratio of P.T = Vp
Vs - p x Vs
100 (3)
where Is and Vs are rated secondary current for C.T. and rated
secondary voltage for P.T. respectively.
Dividing numerator and denominator of equation 2 and 3 by Is
and Vs respectively
Actual Ratio of C.T. = Ip / Is
1- e x Is / Is
100 (4)
Actual Ratio of P.T. = Vp / Vs
1- p x Vs / Vs
100 (5)
or rewriting equation 4 and 5 it will be seen that
Actual Ratio of C.T. = Nominal Ratio
1- e
100 (6)
Actual Ratio of P.T. = Nominal Ratio
1- p
100 (7)
or simply for C.Ts A.R. = N.R.
1- e 100 (8)
